Illinois Football Recruiting Thread

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#76      
TheGMan
CaptainCrutch said:
Boy, wonder who’s who.

So, theoretically, if one is at 95%, do you mean that the second is at a 65-70% or that the odds of getting both at 65-70%? Because of it it’s the latter….

To solve for the odds of the second event (let's call it Event Gabe), we can use the formula for the probability of two independent events happening together. The probability of both events X and Gabe occurring (P(C ∩ Gabe)) is related to the probabilities of X and Gabe as follows:

\[
P(X \cap Gabe) = P( ) \times P(Gabe \mid X)
\]

where:

- \( P(X) \) is the probability of Event X (95% or 0.95),
- \( P(Gabe \mid X) \) is the probability of Event Gabe happening given that Event X has occurred.

You are given that the probability of both events happening together is between 65% and 70% (or 0.65 to 0.70). So, we have the equation:

\[
P(X \cap Gabe) = P(C) \times P(Gabe) = 0.65 \text{ to } 0.70
\]

Now, solve for \( P(Gabe) \):

\[
P(Gabe) = \frac{P(X \cap Gabe)}{P(X)}
\]

Substitute the values:

\[
P(Gabe) = \frac{0.65}{0.95} \approx 0.684 \quad \text{to} \quad P(Gabe) = \frac{0.70}{0.95} \approx 0.737
\]

So, the probability of Event Gabe occurring is approximately between **68.4% and 73.7%**.
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Homer Simpson Nerd GIF
 
#78      
Indy Illini Fan
Username said:
Can you give us any indication what schools are not living up to transfers' expectations? Is this a result of unfulfilled NIL promises or more that the culture here is just better? I'm sure you can't share names of specific recruits/former players, but anything you could share generally would be awesome.
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Pretty clear a couple times this year who wasn’t living up to their promises …

Does Michigan really pony up the $12 million for the Underwood kid ?? I’ll be pretty surprised if that turns out to be the real number …
 
#85      
Carter Waller
CaptainCrutch said:
Boy, wonder who’s who.

So, theoretically, if one is at 95%, do you mean that the second is at a 65-70% or that the odds of getting both at 65-70%? Because of it it’s the latter….

To solve for the odds of the second event (let's call it Event Gabe), we can use the formula for the probability of two independent events happening together. The probability of both events X and Gabe occurring (P(C ∩ Gabe)) is related to the probabilities of X and Gabe as follows:

\[
P(X \cap Gabe) = P( ) \times P(Gabe \mid X)
\]

where:

- \( P(X) \) is the probability of Event X (95% or 0.95),
- \( P(Gabe \mid X) \) is the probability of Event Gabe happening given that Event X has occurred.

You are given that the probability of both events happening together is between 65% and 70% (or 0.65 to 0.70). So, we have the equation:

\[
P(X \cap Gabe) = P(C) \times P(Gabe) = 0.65 \text{ to } 0.70
\]

Now, solve for \( P(Gabe) \):

\[
P(Gabe) = \frac{P(X \cap Gabe)}{P(X)}
\]

Substitute the values:

\[
P(Gabe) = \frac{0.65}{0.95} \approx 0.684 \quad \text{to} \quad P(Gabe) = \frac{0.70}{0.95} \approx 0.737
\]

So, the probability of Event Gabe occurring is approximately between **68.4% and 73.7%**.
Click to expand...
Huge.
 
#93      
madillini4
I mean you can be an “insider” too if you pay for the Illini 247 premium lol.
 
#94      
SescIllini
Lowery has a nice burst of speed for the clips from Syracuse. Didn't see him on the Wisconsin depth chart, two deep. Not sure if he played much with them.
 
#95      
Ill in Cols
CaptainCrutch said:
Boy, wonder who’s who.

So, theoretically, if one is at 95%, do you mean that the second is at a 65-70% or that the odds of getting both at 65-70%? Because of it it’s the latter….

To solve for the odds of the second event (let's call it Event Gabe), we can use the formula for the probability of two independent events happening together. The probability of both events X and Gabe occurring (P(C ∩ Gabe)) is related to the probabilities of X and Gabe as follows:

\[
P(X \cap Gabe) = P( ) \times P(Gabe \mid X)
\]

where:

- \( P(X) \) is the probability of Event X (95% or 0.95),
- \( P(Gabe \mid X) \) is the probability of Event Gabe happening given that Event X has occurred.

You are given that the probability of both events happening together is between 65% and 70% (or 0.65 to 0.70). So, we have the equation:

\[
P(X \cap Gabe) = P(C) \times P(Gabe) = 0.65 \text{ to } 0.70
\]

Now, solve for \( P(Gabe) \):

\[
P(Gabe) = \frac{P(X \cap Gabe)}{P(X)}
\]

Substitute the values:

\[
P(Gabe) = \frac{0.65}{0.95} \approx 0.684 \quad \text{to} \quad P(Gabe) = \frac{0.70}{0.95} \approx 0.737
\]

So, the probability of Event Gabe occurring is approximately between **68.4% and 73.7%**.
Click to expand...
User name doesn't check out. #CaptainCrunch
 
#99      
blackdog
SescIllini said:
Lowery has a nice burst of speed for the clips from Syracuse. Didn't see him on the Wisconsin depth chart, two deep. Not sure if he played much with them.
Click to expand...

The article said he had almost 372 snaps so definitely got some playing time but pretty limited stats from all those snaps.
 
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